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Federal Way Public Schools  
Algebraic Sense
Lesson 19
Patterns and Functions
  Objectives/Vocab/Tips > Examples 1 | 2 | 3 | 4 > Practice: 1 | 2 | 3 > Reflection

Example 3:

Choose the correct linear equation for the table given

  1. X = 2Y - 1
  2. Y = 2X - 1
  3. X = Y + 2
  4. Y = X - 2
X
Y
1
1
5
3
7
4

There are a couple of ways to solve this problem. Probably the easiest way would be to go through your list of given equations and begin substituting the values of X and Y as given in the table. Once you find the equation that has all three pairs of X and Y that work, you have found the correct answer.

As soon as you find one set of X and Y that won't work for the equation, you can move on to the next equation.

Let's begin with the letter D, since we seem to start with letter A all the time. Let's substitute 1 for X and 1 for Y and see if the equation works.

Y = X - 2
1 = 1 - 2
1 = -1
This statement isn't true, so we can move on to the next equation, letter C.

X = Y + 2
1 = 1 + 2
1 = 3
This statement isn't true either since 1 doesn't equal 3. Move on to the next equation, letter B.

Y = 2X - 1
1 = 2(1) - 1
1 = 2 - 1
1 = 1

The first numbered pair works, so let's try the next one.

Y = 2X - 1
3 = 2(5) - 1
3 = 10 - 1
3 = 9

Since the second numbered pair doesn't work, we know that this equation doesn't work for all points. So it is on to the last one, letter A.

X = 2Y - 1
1 = 2(1) - 1
1 = 2 - 1
1 = 1

So far so good. Let's try another set of numbers.

X = 2Y - 1
5 = 2(3) - 1
5 = 6 - 1
5 = 5

Another one works! This one is looking good. One more to try to make sure.

X = 2Y - 1
7 = 2(4) - 1
7 = 8 - 1
7 = 7

Since all three pairs of X and Y worked with the equation, you know that your answer to this problem is letter A, X = 2Y - 1. Of course it would be letter A when we decide to start from the bottom and work our way up this time.

Final answer is letter A.

 

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