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Algebraic Sense
Lesson 21
Evaluation and Solving
  Objectives/Vocab/Tips > Examples 1 | 2 | 3 | 4 > Practice: 1 | 2 | 3 | 4 > Reflection

Example 4:

If 4y + 7 > 15, then y is:

  1. y > 2
  2. y < 2
  3. y < 2
  4. y > 2

To solve this problem you want to do the following:

4y + 7 > 15

4y + 7 - 7 > 15 - 7 (In order to get y by itself, you will want to add the opposite of + 7 which is to subtract 7 or adding a negative 7. Once again, you need to make sure that if you do something to one side of the equation you must do the same thing to the other side.)

4y + 0 > 8 (Simplify.)

4y > 8 (Simplify.)

4y/4 > 8/4 (To get y by itself you need to multiply 4 by its reciprocal or divide by the same number. Again, since you are dividing by 4 on one side you need to divide by 4 on the other side.)

y > 2

Now that you have the answer to the problem, your answer is letter D.

Practice 1 >>

 

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